(2x+1)(2x^2+5x-1)=d

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Solution for (2x+1)(2x^2+5x-1)=d equation:


Simplifying
(2x + 1)(2x2 + 5x + -1) = d

Reorder the terms:
(1 + 2x)(2x2 + 5x + -1) = d

Reorder the terms:
(1 + 2x)(-1 + 5x + 2x2) = d

Multiply (1 + 2x) * (-1 + 5x + 2x2)
(1(-1 + 5x + 2x2) + 2x * (-1 + 5x + 2x2)) = d
((-1 * 1 + 5x * 1 + 2x2 * 1) + 2x * (-1 + 5x + 2x2)) = d
((-1 + 5x + 2x2) + 2x * (-1 + 5x + 2x2)) = d
(-1 + 5x + 2x2 + (-1 * 2x + 5x * 2x + 2x2 * 2x)) = d
(-1 + 5x + 2x2 + (-2x + 10x2 + 4x3)) = d

Reorder the terms:
(-1 + 5x + -2x + 2x2 + 10x2 + 4x3) = d

Combine like terms: 5x + -2x = 3x
(-1 + 3x + 2x2 + 10x2 + 4x3) = d

Combine like terms: 2x2 + 10x2 = 12x2
(-1 + 3x + 12x2 + 4x3) = d

Solving
-1 + 3x + 12x2 + 4x3 = d

Solving for variable 'x'.

Reorder the terms:
-1 + -1d + 3x + 12x2 + 4x3 = d + -1d

Combine like terms: d + -1d = 0
-1 + -1d + 3x + 12x2 + 4x3 = 0

The solution to this equation could not be determined.

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